Answer:
3. x = 17
4. a. m<NMP = 48°
b. m<NMP = 60°
Step-by-step explanation:
3. Given that <BAM = right angle, and
m<BAM = 4x + 22, set 90° equal to 4x + 22 to find x.
4x + 22 = 90
Subtract 22 from both sides
4x + 22 - 22 = 90 - 22
4x = 68
Divide both sides by 4
4x/4 = 68/4
x = 17
4. a. m<NMQ = right angle (given)
m<PMQ = 42° (given)
m<PMQ + m<NMP = m<NMQ (angle addition postulate)
42 + m<NMP = 90 (substitution)
m<NMP = 90 - 42 (subtracting 42 from each side)
m<NMP = 48°
b. m<NMQ = right angle (given)
m<NMP = 2*m<PMQ
Let m<PMQ = x
m<NMP = 2*x = 2x
2x + x = 90° (Angle addition postulate)
3x = 90
x = 30 (dividing both sides by 3)
m<PMQ = x = 30°
m<NMP = 2*m<PMQ = 2*30
m<NMP = 60°
Answer:
4
Step-by-step explanation:
4-2
The perimeter of the large triangle = 2 * perimeter of the small one so:-
2x + 4x + 2(4x + 1) = 62
14x = 60
x = 4 2/7 answer
The geometric mean of 2 & 200 is *(20)*
