Explanation:
The perimeter of the track is the two circumferences of the semicircles (when combined, they form one circle, so we can just find the circumference of the circle) added to the lengths of the rectangle (
160
meters).
To find the circumference of the circle, we need to know the diameter.
Circumference of a circle:
d
π
or
2
r
π
, where
d
represents diameter and
r
represents radius
The diameter of the circle happens to be the same as the width of the rectangle. We know that the area of a rectangle is found by multiplying its length by its width. We know that the area is
14400
and that its length is
160
.
Width: area divided by length
14400
160
=
90
The diameter of the circle and the width of the rectangle is
90
meters.
Circumference:
90
⋅
π
=
90
π
→
If you are using an approximation such as 3.14 for
π
, multiply that by 90
Add
160
⋅
2
to the circumference since the lengths of the rectangle are also part of the perimeter.
160
⋅
2
=
320
90
π
+
320
i hope it helps you ok please mark ❣️ me as brainlist
Step-by-step explanation:
to convert pounds into ounces you'd
actually multiply 16 by 30:
30 * 16
you're doing this because if one pound equals 16 ounces, if you have 30 pounds then you must've had more ounces. therefore you'd multiply.
which is 480 pounds
Enjoy!
<u>Find fraction of snappers and catfish:</u>
1/3 + 2/9 = 3/9 + 2/9 = 5/9
<u>Find fraction of goldfish:</u>
1 - 5/9 = 4/9
4/9 = 40 goldfish
1/9 = 40 ÷ 4 = 10
9/9 = 10 x 9 = 90
Answer: 90 fish in the tank
Answer:
![(f\circ g)(x)= x + 4](https://tex.z-dn.net/?f=%28f%5Ccirc%20g%29%28x%29%3D%20x%20%2B%204)
Step-by-step explanation:
<u>Composite Function</u>
Given f(x) and g(x) as real functions, the composite function
is defined as:
![(f\circ g)(x)=f(g(x))](https://tex.z-dn.net/?f=%28f%5Ccirc%20g%29%28x%29%3Df%28g%28x%29%29)
It can be found by substituting g into f.
We are given the functions:
f(x) = -x + 3
g(x) = -x -1
Find
![(f\circ g)(x)=f(g(x))= - (-x -1) + 3](https://tex.z-dn.net/?f=%28f%5Ccirc%20g%29%28x%29%3Df%28g%28x%29%29%3D%20-%20%28-x%20-1%29%20%2B%203)
Removing parentheses:
![(f\circ g)(x)= x + 1 + 3](https://tex.z-dn.net/?f=%28f%5Ccirc%20g%29%28x%29%3D%20x%20%2B%201%20%2B%203)
Simplifying:
![\mathbf{(f\circ g)(x)= x + 4}](https://tex.z-dn.net/?f=%5Cmathbf%7B%28f%5Ccirc%20g%29%28x%29%3D%20x%20%2B%204%7D)
Answer:
There is not enough information to answer this question
Step-by-step explanation: