Question

What is the answer to this problemy%2B40%7D" id="TexFormula1" title="\frac{5y-20}{3y+15} .\frac{7y+35}{10y+40}" alt="\frac{5y-20}{3y+15} .\frac{7y+35}{10y+40}" align="absmiddle" class="latex-formula">

Answer 1

Answer:

7(y-4)

---------

6(y+4)

Step-by-step explanation:

5y-20        7y+35

------------ * ------------

3y+15           10y +40

Factor

5(y-4)     7(y+5)

--------  * -----------

3(y+5)     10(y+4)

Cancel like terms

(y-4)     7

--------  * -----------

3            2(y+4)

7(y-4)

---------

6(y+4)