Answer:
We have that the sum of two numbers is 9
this can be written as:
x + y = 9
where x is the larger number.
Now we want to write:
"the difference between one more than the larger number and twice the smaller number"
First, remember that the difference between A and B is:
A - B
Then "the difference between one more than the larger number and twice the smaller number"
is:
"one more than the larger number" = ( x + 1)
"twice the smaller number" = 2*y
the difference between these is:
(x + 1) - 2*y
Now we can simplify:
We know that:
x + y = 9
then:
y = 9 - x
replacing that in the equation:
(x + 1) - 2*y
we would get:
x + 1 - 2*(9 - x)
x + 1 -18 + 2x
(x + 2x) + (1 - 18)
3x - 17
This means that we can write:
"the difference between one more than the larger number and twice the smaller number"
as: 3x - 17
Answer:
0
Step-by-step explanation:
any log with a base of one and it becomes logv5 (1) after logv5(logV3 (3) because log3(3) equal one so then logv5 (1) is 0
The answer is 30,60,90. Because 60 is twice the number 30 and 90 is three times the first number.
Answer: 20/3
So when solving this equation first distribute our 3,we will now have 3x-15=5.
Next we will Add 15 to both sides of our equation. Now we have 3x=20.Then divide our terms,and you will have 3x/3 = 20/3
<u>This will leave you with 1x=20/3. </u>
So the X is 20/3.
Hope that helped!
