To get the inverse "relation" of an expression, we first off, do a quick switcharoo of the variables, and then solve for "y", so let's proceed,

and yes, the domain for the range 0 ⩽ x
<span>⩽ 2, let's get instead the "range" of the original function,
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
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The answer to your problem is -2.1.
It is 1a over bd and 8 over k
12, 18 , 24, 30, 36, 42….