If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
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Answer:
f−1 (x)= x/3 +1 /3
Step-by-step explanation:
Answer:
<h2>270 ft²</h2>
Step-by-step explanation:
<h3>METHOD 1:</h3>
<em>Look at the picture</em>
We can divide a given polygon into three rectangles:
The formula of an area of a rectangle <em>l × w </em>:
Calculate the area of each of the rectangles:
The area of the given polygon:
<h3 /><h3>METHOD 2:</h3>
<em>Look at the second picture</em>.
We subtract the field of the smaller rectangle (<em>11ft × 6ft</em>) from the field of the large rectangle (<em>21ft × 16ft</em>):
22/3 sorry I accidentally deleted steps
-9s2+4s-2. Just gotta find s unless that is what you are looking for
