Answer:
A acute
Step-by-step explanation:
cause an acute it between 0-90 degrees
The result of our calculations about the rate and time are:
<h3>What is rate?</h3>
Rate can be regarded as the given object with respect to time.
falcon flies= 800,000 meters
t= 4 hours
We were given the formula as (d = rt)
d= distance
r = rate
t = time
We can make our calculations as:
part a:
r=d/t
part b:
falcon's rate in meters per hour = 800,000 meters / 4 hours = 200000m/hr
part c:
falcon's rate in kilometers per hour=(200000m/hr *(1/1000)=200km/hr
part d:
km/hr
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Answer:
Negative 35 divided by 5.
Step-by-step explanation:
I got this answer by using process of elimination. So let's try it shall we?
2+12
This has to positive numbers in the process of addition so this would be a positive number with the answer of 14.
-3 x -8
This equation has two negatives being multiplied by each other hence cancelling each other out so the answer would be positive.
10 - (-18)
Much like the last equation there are to negatives, but this equation is subtracting by a negative so the negatives next to each other in that way would cancel each other out leaving you with a positive 28.
-35 / 5
Seeing as we have checked every other equation this one must be negative but lets check. When you divide a negative by a positive the positive would automatically take the form of the negative number, because it does not have a negative of its own to cancel the negative out so this must have a negative outcome.
Answer:
a. Using the inverse demand for each, solve for the social marginal benefit curve.
Bob: Scott:
Q = 40-P Q = 30 – P
(-1)Q – 40 = -P(-1) (-1)Q – 30 = -2P
40 – Q = P 30 – Q = 2P
((30 – Q) = 2P)/2
15 – 1/2Q = P
P = 15 – 1/2Q + 40 – Q
P = 55 – 1.5Q
Scott is no longer willing to pay anything when Q >30
Social Marginal Benefit curve: Q = 40 - P
b. What is the socially efficient amount of plowing?
SMB = SMC
35 = 55 – 1.5Q
Subtract from both sides and rearrange
1.5Q = 20
Q = 13.33
c. Suppose the input costs of plowing fell and marginal costs of plowing were now constant at $5.
55 – 1.5Q = 5
55-5 = 1.5Q
50 = 1.5Q
33.3 = Q*