Given:
For cylinder P: radius = 4.25 in. and height = 14 in.
For cylinder Q: radius = 7 in. and height = 8.5 in.
To find:
The volume of each cylinder.
Solution:
Volume of a cylinder is
where, r is radius and h is height. Use 3.14 for 
.
Using the above formula, the volume of cylinder P is
Using the above formula, the volume of cylinder Q is
Therefore, the volume of cylinder P is 794.03 sq. in. and volume of cylinder Q is 1307 sq. in.
Answer:
346 2/3 yards
Step-by-step explanation:
A football field is 100 yards long with each end zone being 10 years long, meaning the total length is 120 yards.
The width is 53 1/3 yards.
The perimeter is all the sides added, and a rectangle's, the shape of the field's, formula is p = 2l + 2w.
So if we plug it in and add it all up:
120 + 120 + 53 1/3 + 53 1/3
Perimeter = 346 2/3
A.) A Triangle cannot be both "Obtuse and Right"
[ It must be either Obtuse, Right or Acute. Never with two multiple properties ]
Hope this helps!
Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
