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3 years ago

8

A runner covers a distance of 1200m with an average speed of 4m/s. How long does it take to run this distance? Then calculate th

e time in min.
Be the first answer for Brainliest, please I need help.

1 answer:

Nadusha1986 [10]3 years ago

8 0

Answer:

5mins

Step-by-step explanation:

well i did 1200 divided y 4 then divided that answer by 60

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This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

olga nikolaevna [1]

$f(x_1,\ldots,x_n)=x_1+\cdots+x_n=\displaystyle\sum_{i=1}^nx_i$

${x_1}^2+\cdots+{x_n}^2=\displaystyle\sum_{i=1}^n{x_i}^2=4$

The Lagrangian is

$L(x_1,\ldots,x_n,\lambda)=\displaystyle\sum_{i=1}^nx_i+\lambda\left(\sum_{i=1}^n{x_i}^2-4\right)$

with partial derivatives (all set equal to 0)

$L_{x_i}=1+2\lambda x_i=0\implies x_i=-\dfrac1{2\lambda}$

for $1\le i\le n$ , and

$L_\lambda=\displaystyle\sum_{i=1}^n{x_i}^2-4=0$

Substituting each $x_i$ into the second sum gives

$\displaystyle\sum_{i=1}^n\left(-\frac1{2\lambda}\right)^2=4\implies\dfrac n{4\lambda^2}=4\implies\lambda=\pm\frac{\sqrt n}4$

Then we get two critical points,

$x_i=-\dfrac1{2\frac{\sqrt n}4}=-\dfrac2{\sqrt n}$

or

$x_i=-\dfrac1{2\left(-\frac{\sqrt n}4\right)}=\dfrac2{\sqrt n}$

At these points we get a value of $f(x_1,\cdots,x_n)=\pm2\sqrt n$ , i.e. a maximum value of $2\sqrt n$ and a minimum value of $-2\sqrt n$ .

6 0

3 years ago

Will mark brainliest

Anni [7]

Answer:

1.

Anya could find out her volume by multiplying 1.5*1.5*4 and then subracting that from 11*8.5.

Terrence could find out his volume by multiplying 3*3*4 and then subtracting that from 11*8.5

Anya's suggestion would maker a larger volume.

There can be 2 different volumes because someone might cut out more than the other person.

2.

I think there's something missing from this question.

6 0

3 years ago

Read 2 more answers

I need help on this question can some help

guapka [62]

Answer:There’s a that you can download with a ton of edginuity answers if you type down edginuity answers and hit the pdf by reservamesa and you can find some.

Step-by-step explanation:

5 0

3 years ago

What is the answer to the question 25% of what is 21?

g100num [7]

If we call the number "x" then:
x*25%=21
x*25/100=21
x=21*4
x=84

Hope this helps. :)

8 0

3 years ago

Read 2 more answers

Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.

leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

$12x-5y+14=0 \\ 12x-5y-14=0$

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1$

$\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1$

$\Rightarrow 12h-5k-1=\pm 13$

$\Rightarrow 12h-5k=\pm 14$

$\Rightarrow 12h-5k=14,\ 12h-5k=-14$

$\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0$

$\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0$

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0

2 years ago