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aleksandrvk [35]
3 years ago
8

On a blueprint the length of a wall is 5 centimeters. If the actual length of the wall is 15 feet, what is scale of the blueprin

t
Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0

Answer:

The wall is 90 meters wide.

Step-by-step explanation:

1. set up and solve a proportion to find the value of w like this:

1cm=6cm

15m=wm

2. cancel out the like units on both sides of the equation

1=6

15=w

3. Equate the cross products, and then solve for w:

1*w=15*6

w=90                                                                                                                                          The actual width of the wall is 90 meters.

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Answer:

B.) 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

x - y = -1

3x + 5y = 21

<u>Step 2: Rewrite Systems</u>

x - y = -1

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<u>Step 3: Redefine Systems</u>

x = y - 1

3x + 5y = 21

<u>Step 4: Solve for </u><em><u>y</u></em>

<em>Substitution</em>

  1. Substitute in <em>x</em>:                              3(y - 1) + 5y = 21
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3 years ago
Answer please. If you answer, you get 44 points. I don't use the points here. So answer please. I want full work.
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Step-by-step explanation:

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Answer:

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