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Korolek [52]
3 years ago
11

Which expression is equivalent to 4 over 9 x 7

Mathematics
1 answer:
wolverine [178]3 years ago
3 0

Answer:

3 1/9

Step-by-step explanation:

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Find the inverse of P(x)=-15x^2+350x-2000 and state it’s domain.
natima [27]

Answer:

The function given is:

P(x) = 15x² + 350x - 2000

or

y = 15x² + 350x - 2000

Interchange x and y:

x = 15y² + 350y - 2000

x = (y√15)² + 2(y√15)(45.19) + (45.19)² - (45.19)² - 2000

x = ( y√15 + 45.19)² - 4042.14

( y√15 + 45.19)² = x + 4042.14

Take square root:

y√15 + 45.19 = (√(x + 4042.14))

y√15 =  (√(x + 4042.14)) - 45.19

y = \sqrt{\frac{x+4042.14}{15}}-11.67

f^{-1}(x) = \sqrt{\frac{x+4042.14}{15}}-11.67

The minimum value of x, for which function is defined and real, is x= -4042.14

Hence, the range of inverse is x ≥ -4042.14

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3 years ago
A 3 cm border is cut from a rectangular sheet
Vsevolod [243]

breadth = length²

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3 0
3 years ago
The probability that a randomly-selected 2 year old male salamander will live to be three years old is 0.9 567 what is the possi
melisa1 [442]

Answer:

a. Probability = 0.9153

b. Probability = 0.6714<em></em>

c. P(atleast\ one) = 0.99999999999<em />

d. It is not unusual

Step-by-step explanation:

Represent the given probability with P(T)

P(T) = 0.9567

<em>Solving (a): Probability two selected will live to be three years old</em>

<em>This is calculated as:</em>

<em></em>Probability = P(T) * P(T)<em></em>

<em></em>Probability = 0.9567 * 0.9567<em></em>

<em></em>Probability = 0.91527489<em></em>

<em></em>Probability = 0.9153<em> --- </em><em>Approximated</em>

<em />

<em>Solving (b): The probability that nine selected will live to be three years old</em>

<em>This is calculated as:</em>

<em></em>Probability = (P(T))^9<em></em>

<em></em>Probability = 0.9567^9<em></em>

<em></em>Probability = 0.67140097202<em></em>

<em></em>Probability = 0.6714<em>   --- </em><em>Approximated</em>

<em />

<em>Solving (c): Probability that at least one of the nine selected will not live to be three years old</em>

<em />

<em>To solve this, we need to determine the probability that none of the 9 selected will live to be 3 years old.</em>

<em>But first, we need to solve the probability that a selected male will not live to be 3 years old.</em>

<em>This is represented as: P(T') and is calculated as thus:</em>

<em />P(T) + P(T') = 1<em />

<em />P(T') = 1 - P(T)<em />

<em />P(T') = 1 - 0.9567<em />

<em />P(T') = 0.0433<em />

<em>The probability that none of the nine will live to be 3 years old is:</em>

<em />P(none) = (P(T'))^9<em />

<em />P(none) = 0.0433^9<em />

<em />

<em>So, the required probability is calculated as thus;</em>

<em />P(atleast\ one) = 1 - P(none)<em />

<em />P(atleast\ one) = 1 - 0.0433^9<em />

<em />P(atleast\ one) = 0.99999999999<em />

<em />

<em>Solving (d): Would (c) be unusual </em>

<em></em>

<em>This probability is calculated in (c) above.</em>

<em />P(atleast\ one) = 0.99999999999<em />

<em />

<em>Because it approximates to 1, we can conclude that it is not unusual</em>

7 0
3 years ago
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