The two number are 39 and 13
<em><u>Solution:</u></em>
Let the two numbers be "a" and "b"
Let the larger number be "a" and the smaller number be "b"
<em><u>Given that, sum of two numbers is 52</u></em>
a + b = 52 ---------- eqn 1
<em><u>One number is 3 times as large as the other number</u></em>
Larger number = 3 times smaller number
a = 3b -------- eqn 2
<em><u>Let us solve eqn 1and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
3b + b = 52
4b = 52
b = 13
<em><u>Substitute b = 13 in eqn 2</u></em>
a = 3(13)
a = 39
Thus the two number are 39 and 13
Answer:
D A = (1/2) (y₂ - y₁)(x₃ - x₁)
Step-by-step explanation:
b = (y₂ - y₁)
h = (x₃ - x₁)
A = (1/2)bh
A = (1/2) (y₂ - y₁)(x₃ - x₁)
The answer is D, (1/3, 4).
Hope this helped!
Answer:
Independent-samples t-test.
Step-by-step explanation:
We are looking for the appropriate design for testing the significance of the difference between the means.
Now, there is a parametric test known as the Independent Samples t Test and what this test does is that it compares the mean of two independent groups in order to find out whether there is statistical evidence that the related population mean is significantly different.
Thus, the test to be used here is Independent-samples t-test.
