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3 years ago

Please answer this probability question.

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

5 0

Answer:

$\large\boxed{\large\boxed{1/9}}}$

Explanation:

1. Sample space:

Since the each die has 6 different possible outcomes, the number of ways that can the two dice land is 6 × 6 36

2. Number of favorable outcomes:

1 + 1 = 2

1 + 3 = 4

2 + 2 = 4

3 + 1 = 4

Those are a total of 4 different outcomes for the sum of the result rolled is 2 or 4.

3. Probability:

Probability = # favorable outcomes / # possible outcomes

Probability = 4 / 36 = 1 / 9

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Compute the value of the discriminant and give the number of real solutions of the Quadratic equation 3x^2+9x-1=0 PLSS HELPP

FrozenT [24]

Answer:

Discriminant = 93, two real roots/solutions

Step-by-step explanation:

Discriminant = b² - 4ac = (9)² - 4(3)(-1) = 81 + 12 = 93

Since 93>0, the quadratic equation has two real roots/solutions.

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3 years ago

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taurus [48]

Answer:

1.No

2.No

Step-by-step explanation:

5=x+5 x=10

5=10+5

5=15 is not solution

12x=196 x=7

12*7=196

84=196

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3 years ago

What is the inverse of the relation {(-3, 5), (2, -2), (0, 1)}?

olya-2409 [2.1K]

The inverse of a relation just switches the x and y values.
{(-3,5), (2,-2),(0,1)}
Inverse = {(5,-3),(-2,2),(1,0)}
Option 2

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4 years ago

a cook needs 12 pounds of flour he wants to spend the least amount of money if a 2 pound bag costs $1.59 and a 5 pound bag costs

Virty [35]

He should buy two 5 pound bags and one 2 pound bag.

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3 years ago

Read 2 more answers

Let f be a continuous function defined on the interval [0,1] such that f(0) = f(1). Show that there exists a number 0 <= a &l

Leni [432]

Explanation:

In order to prove that affirmation, we define the function g over the interval [0, 1/2] with the formula $g(x) = f(x+1/2)-f(x) .$

If we evaluate g at the endpoints we have

g(0) = f(1/2)-f(0) = f(1/2) - f(1) (because f(0) = f(1))

g(1/2) = f(1) - f(1/2) = -g(0)

Since g(1/2) = -g(0), we have one chance out of three

g(0) > 0 and g(1/2) < 0
g(0) < 0 and g(1/2) > 0
g(0) = g(1/2) = 0

We will prove that g has a zero on [0,1/2]. If g(0) = 0, then it is trivial. If g(0) ≠ 0, then we are in one of the first two cases, and therefore g(0) * g(1/2) < 0. Since f is continuous, so is g. Bolzano's Theorem assures that there exists c in (0,1/2) such that g(c) = 0. This proves that g has at least one zero on [0,1/2].

Let c be a 0 of g, then we have

$0 = g(c) = f(c+1/2)-f(c)$

Hence, f(c+1/2) = f(c) as we wanted.

5 0

3 years ago