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Mariulka [41]
3 years ago
6

Please answer this probability question.

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

          \large\boxed{\large\boxed{1/9}}}

Explanation:

<u></u>

<u>1.  Sample space:</u>

Since the each die has 6 different possible outcomes, the number of ways that can the two dice land is 6 × 6 36

<u>2. Number of favorable outcomes:</u>

  • 1 + 1 = 2
  • 1 + 3 = 4
  • 2 + 2 = 4
  • 3 + 1 = 4

Those are a total of 4 different outcomes for the sum of the result rolled is 2 or 4.

<u>3. Probability:</u>

<u />

  • Probability = # favorable outcomes / # possible outcomes

  • Probability = 4 / 36 = 1 / 9

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Answer:

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a) 2\sqrt{2}=( \sqrt{2}  )^2.\sqrt{2}=(\sqrt{2})^3 = \sqrt{2^3} =\sqrt{8}

b)-7\sqrt{3} =-(\sqrt{7} )^2\sqrt{3} =-\sqrt{7^2.3} =-\sqrt{147}

c)\frac{1}{3} \sqrt{18b} =\frac{1}{3} \sqrt{9.2.b} =\frac{1}{3} \sqrt{3^2.2.b} =\frac{1}{3} \times 3\sqrt{2.b} =\sqrt{2.b}

d)5\sqrt{y} =\sqrt{5^2} \sqrt{y}=\sqrt{25y}

e)-6\sqrt{2a} =-\sqrt{6^2}\sqrt{2a}  = -\sqrt{36.2a} =-\sqrt{72a}

f)-0.1\sqrt{200c}=-\frac{1}{10}  \sqrt{10^2.2c} =-\frac{1}{10}\times10  \sqrt{2c}=-  \sqrt{2c

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