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2 years ago

Express the following ratio as a fraction in simplest form. $32 for 10 tickets

Mathematics

1 answer:

nordsb [41]2 years ago

6 0

Answer:

$16/5tickets

Step-by-step explanation:

it be in simplest form mate.

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Misty took a multiple choice test in science that had 50 questions. If the relationship between the number she got correct and t

Alex

In this case, the total number of questions in the test is 50. The possible outcome for the question would be answered wrong, answered correctly or not answered. To know the amount of the correct answer, you need to multiply the incorrect with correct/incorrect ratio. The equation would be:
correct answer: 9 answer * 7/3= 21 answer.

Then for this test misty has:
9 incorrect answer
21 correct answer
20 blank/ not answered

4 0

3 years ago

Is 8 a solution to 3 over 4 x = 6

SSSSS [86.1K]

Answer:

Yes, 8 is a solution

Step-by-step explanation:

<u>Step 1: Check if solution</u>

<u /> $\frac{3}{4} x = 6$

$\frac{3}{4} (8) = 6$

$\frac{24}{4} = 6$

$6=6$

Answer: Yes, 8 is a solution

6 0

3 years ago

Read 2 more answers

Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = yzi + 4xzj + ex

natima [27]

Answer:

The result of the integral is 81π

Step-by-step explanation:

We can use Stoke's Theorem to evaluate the given integral, thus we can write first the theorem:

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S$

Finding the curl of F.

Given $F(x,y,z) = < yz, 4xz, e^{xy} >$ we have:

$curl \vec F =\left|\begin{array}{ccc} \hat i &\hat j&\hat k\\ \cfrac{\partial}{\partial x}& \cfrac{\partial}{\partial y}&\cfrac{\partial}{\partial z}\\yz&4xz&e^{xy}\end{array}\right|$

Working with the determinant we get

$curl \vec F = \left( \cfrac{\partial}{\partial y}e^{xy}-\cfrac{\partial}{\partial z}4xz\right) \hat i -\left(\cfrac{\partial}{\partial x}e^{xy}-\cfrac{\partial}{\partial z}yz \right) \hat j + \left(\cfrac{\partial}{\partial x} 4xz-\cfrac{\partial}{\partial y}yz \right) \hat k$

Working with the partial derivatives

$curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(4z-z\right) \hat k\\curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k$

Integrating using Stokes' Theorem

Now that we have the curl we can proceed integrating

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S$

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot \hat n dS$

where the normal to the circle is just $\hat n= \hat k$ since the normal is perpendicular to it, so we get

$\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S \left(\left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k\right) \cdot \hat k dS$