For the seagull to catch the crab, h(t)=g(t) so:
-16t^2+45=-13t+23 add 16t^2 to both sides
45=16t^2-13t+23 subtract 45 from both sides
16t^2-13t-22=0 using the quadratic equation:
t=(13±√1577)/32, since t>0
t=(13+√1577)/32 seconds
t≈1.65 seconds (to nearest hundredth of a second)
And the height that this occurs using either original equation is:
h((13+√1577)/32)≈1.59 ft (to nearest hundredth of a foot)
Answer: It's from 11:02 till 11:35. hbu?
Step-by-step explanation:
I do it online and I be eating 24/7
B I think.correct if I’m wrong
Its b= -0.2 or b= 1/-5 whichever one works best
Step-by-step explanation:
I assume
SR = 2x + 23
RQ = x + 21
if that is true, then the situation is completely simple :
14 = (2x + 23) + (x + 21) = 3x + 44
3x = -30
x = -10
SR = 2×-10 + 23 = -20 + 23 = 3
RQ = -10 + 21 = 11
