Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
<h3><u>The length is equal to 25.</u></h3><h3><u>The width is equal to 15.</u></h3>
l = 2w - 5
2l + 2w = 80
We have a value for l, so we can plug it into the second equation to solve for w.
2(2w - 5) + 2w = 80
Distributive property.
4w - 10 + 2w = 80
Combine like terms.
6w - 10 = 80
Add 10 to both sides.
6w = 90
Divide both sides by 6.
w = 15
Now that we have a value for w, we can plug it into the original equation to solve for l.
l = 2(15) - 5
l = 30 - 5
l = 25
Answer:
So there is a 2 in 13 chance to pull out either an ace or king from the deck
Step-by-step explanation: