Answer:
7560 in^3
Step-by-step explanation:
Hello! The first thing that we must take into account to solve this problem is that the volume of any solid is equal to the transverse area by the height, in this case we must find the area of the trapezoid and then multiply it by the height
V=AL
V= Volume
A=area
L=height=9in
finding area of trapezoid

To know what each variable corresponds to, please see the attached file

finally multiply the area by the height of the box(9in)
V=AL
V=(840in^2)(9in)=7560in^3
the volume of the flower box is 7560 in^3
In this case you go to the thousandths so,-.261, -0.262 ,-0.263,-0.264,and so on.you could even go to the millionths,for example -0.2611
(a).
The product of two binomials is sometimes called FOIL.
It stands for ...
the product of the First terms (3j x 3j)
plus
the product of the Outside terms (3j x 5)
plus
the product of the Inside terms (-5 x 3j)
plus
the product of the Last terms (-5 x 5)
FOIL works for multiplying ANY two binomials (quantities with 2 terms).
Here's another tool that you can use for this particular problem (a).
It'll also be helpful when you get to part-c .
Notice that the terms are the same in both quantities ... 3j and 5 .
The only difference is they're added in the first one, and subtracted
in the other one.
Whenever you have
(the sum of two things) x (the difference of the same things)
the product is going to be
(the first thing)² minus (the second thing)² .
So in (a), that'll be (3j)² - (5)² = 9j² - 25 .
You could find the product with FOIL, or with this easier tool.
______________________________
(b).
This is the square of a binomial ... multiplying it by itself. So it's
another product of 2 binomials, that both happen to be the same:
(4h + 5) x (4h + 5) .
You can do the product with FOIL, or use another little tool:
The square of a binomial (4h + 5)² is ...
the square of the first term (4h)²
plus
the square of the last term (5)²
plus
double the product of the terms 2 · (4h · 5)
________________________________
(c).
Use the tool I gave you in part-a . . . twice .
The product of the first 2 binomials is (g² - 4) .
The product of the last 2 binomials is also (g² - 4) .
Now you can multiply these with FOIL,
or use the squaring tool I gave you in part-b .
Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
Answer:
50b+205
Step-by-step explanation:
Yes sir