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Answer:
a. The answer is: $1,008.40
b. The bond's YTM is 3.343%
c. The current yield is 3.826%
Explanation:
a. Bond price formula: ∑(C* / (1+YTM) )
The price of the bond Intro A with i=1,2...10 is:
∑($1,000 x 3.4% / (1 + 3.3%) ) = $1,008.40
b. The price of the corporate bond which has 22 years to maturity is: $1,202.20
Given that the bond is trading at par value, the bond's YTM is:
[Annual Interest Payment + ((Face Value – Current Price) / (Years to Maturity))] / ( ( Face Value + Current Price ) / 2 )
= [$1,000 x 4.6% + (($1,000 - $1,202.20) / 22)] / (($1,000 + $1,202.20) /2)
= 3.343%
c. The bond's current yield is:
Annual Interest Payment / Current Price = $46 / $1,202.2 = 3.826%
Answer:
- The final temperature in the container with Gold is 27.49 ⁰C
- The final temperature in the container with Iron is 33.01 ⁰C
Therefore, the highest final temperature is obtained in the container with Iron.
Explanation:
Q = mcΔT
Where;
Q is the quantity of heat gained or lost
m is the mass of the metals or water
c is the specific heat capacity
ΔT is the change in temperature, T₂ - T₁
T₂ is the final temperature and T₁ is the initial temperature
Heat lost by metals at 100°C is equal to heat gained by water at 25°C
Specific heat capacity of water = 4.18 J/g°C
Specific heat capacity of gold = 0.129 J/g°C
Specific heat capacity of iron = 0.45 J/g°C
⇒For Gold
-20*0.129*(T₂ - 100) = 18*4.18 (T₂ - 25)
-2.58T₂ +258 = 75.24T₂ - 1881
77.82T₂ = 2139
T₂ = 2139/77.82
T₂ = 27.49 ⁰C
⇒For Iron
-20*0.450*(T₂ - 100) = 18*4.18 (T₂ - 25)
-9T₂ +900 = 75.24T₂ - 1881
84.24T₂ = 2781
T₂ = 2781/84.24
T₂ = 33.01 ⁰C
Therefore, the highest final temperature is obtained in the container with Iron.