Answer:
b. lw $t4, 4($t0)
c. add $t3, $t5, $t4
Explanation:
Pipeline hazard prevents other instruction from execution while one instruction is already in process. There is pipeline bubbles through which there is break in the structural hazard which preclude data. It helps to stop fetching any new instruction during clock cycle.
It would be, <span>the <span>microprocessor.
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It is also a multipurpose and programmable device that accepts inputted data and process the data to provide an output.
Hope this helps!
Answer:
All of the above but I'm not 100% sure.
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