Graph
quadratic function is of the form
In our f(x) there is no x term and constant so we put 0
The value of a=1 , b=0 and c=0
To find vertex , use formula
Plug in the values
=0
Now plug in x=0 in f(x) equation
=0
So vertex is (0,0)
Now we pick some number for x below and above 0
Make a table
x y=x^2
-2 4
0 0
2 4
Now plot all the points (-2,4) (0,0) and (2,4)
The graph is attached below
Answer:
(6,9) nice
Step-by-step explanation:
All we have to do is get y alone and input our values to see if it makes the statement true.
y - 1 = 3(x + 2)
Add 1 to both sides.
y = 3x + 7
y = 3(1) + 7
y = 3 + 7
y = 10
FALSE
y - 2 = 3(x + 1)
Add 2 to both sides.
y = 3x + 3
y = 3(1) + 3
y = 3 + 3
y = 6
FALSE
y + 1 = 3(x - 2)
Subtract 1 from both sides.
y = 3x - 7
y = 3(1) - 7
y = 3 - 7
y = -4
FALSE
y + 2 = 3(x - 1)
Subtract 2 from both sides.
y = 3x -5
y = 3(1) - 5
y = 3 - 5
y = -2
TRUE
The only equation that makes this statement true is D, y + 2 = 3(x - 1).
No
<span>2(9z + 9w) + 12w
= 18z + 18w + 12w
=18z + 30w
not equal </span><span>18w + 30z</span>
To find the area of a figure like this, first split this into two shapes to make things simpler: a 10 by 8 rectangle, and a triangle with a height of 5 and a base of 4. To find the dimensions of the triangle, notice that the base of the entire figure is 12 and once you split the figure into a rectangle and a triangle, you get one side that is 8 which means the base of the triangle must be 4. Now that we know the dimensions of each figure, start by finding the area of each one. To find the area of the rectangle, multiply its length by its width, or 10*8. This would give you 80. Then, find the area of the triangle, which is multiplying its base and height and dividing it by two. This would be (4*5)/2. This would equal 10. Now that we have the area of both the sections in the figure, add them together and you get your answer as 90.