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Ne4ueva [31]
3 years ago
6

Jorge was studying average life expectancy in Europe and how it varies across different countries. He wanted to discover what va

riables were good predictors of life expectancy and identified 3 that he believed could possibly be good predictors:
employment rate,
access to healthcare, and
number of car accidents per year.
He conducted a multiple linear regression analysis using these variables.
When looking over the results of this analysis, he saw
that the scatterplot did not show a linear pattern between each of the explanatory variables and the response variable.
that there was not a funnel shape to the residual vs. predicted plot. that the histogram of the normal quantile plot was fairly normal.
Based on all of these findings,
he can say that the linearity condition _________
the equal variance condition ________
the normality condition _____________
the 10% condition ____________
and the success failure condition __________
Options for each:
A) is not met
B) does not need to be checked for multiple linear regression
C) is met
Mathematics
1 answer:
taurus [48]3 years ago
7 0

Answer:

  • Is not met ( A )
  • Is not met ( A )
  • Does not need to be checked for multiple linear regression ( B )
  • Does not need to be checked for multiple linear regression ( B )

Step-by-step explanation:

Linearity condition is :  <em>NOT MET </em>

The equal variance condition is : <em>NOT MET</em>

The 10% condition :<em> Does not need to be checked for multiple linear regression </em>

The success failure condition : <em>Does not need to be checked for multiple linear regression</em>

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The graph below shows the value of Edna's profits f(t), in dollars, after t months:
umka21 [38]
Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), x=6 and x=18 are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
x=6
x-6=0
x=18
x-18=0

(x-6)(x-18)=x^{2}-6x-18x+108
=x^{2}-24x+108

Now that we have our quadratic function, we are going to use the average formula: m= \frac{f(9)-f(3)}{9-3}
where
f(9) is the function evaluated at  the <span>9th month
</span>f(3) is the function evaluated at the 3rd month 

m= \frac{f(9)-f(3)}{9-3}
m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}
m= \frac{-27-45}{6}
m= \frac{-72}{6}
m=-12

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: <span>B. −11.63 dollars per month.</span>

6 0
3 years ago
Read 2 more answers
What multiplies to give you 15 and adds to give you -8?
Nitella [24]

Answer:

The system of equations is:

        x + y = 15

           xy = 15

Step-by-step explanation:

solve the first for y and substitute in the second:

            y = 15-x

      x(15-x) = 15

     15x - x� = 15

15x - x� - 15 = 0

-x� + 15x - 15 = 0

x� - 15x + 15 = 0

7 0
2 years ago
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The random variable x has the following probability distribution: x f(x) 0 .25 1 .20 2 .15 3 .30 4 .10 a. Is this probability di
Reptile [31]

Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.25           0               0                0

1     0.20        0.20             1              0.20

2    0.15          0.3               4             0.6

3    0.30         0.9               9             2.7

4    0.10          0.4               16             1.6

   ∑P(x)=1     ∑xP(x)=1.8               ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.25+0.20+0.15+0.30+0.10

\sum P(X)=1

Yes it is a probability distribution.

b) The expected value of x is defined as

E(x)=\sum xP(x)=1.8

c) The variance of x is defined as

V=\sum x^2P(x)-(\sum xP(x))^2\\V=5.1-(1.8)^2\\V=5.1-3.24\\V=1.86

d) The standard deviation of x is  defined as

\sigma=\sqrt{V}

\sigma=\sqrt{1.86}

\sigma=1.136

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one customer purchases 8 bags of dog food and 2 bags of dog food. The total weight of the purchases is 44 pounds. Another custom
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Liono4ka [1.6K]

Answer:

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Step-by-step explanation:

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