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Anna35 [415]
3 years ago
9

To review the solution to a similar problem, consult Interactive Solution 1.43. The magnitude of a force vector is 86.4 newtons

(N). The x component of this vector is directed along the +x axis and has a magnitude of 72.3 N. The y component points along the +y axis. (a) Find the angle between and the +x axis. (b) Find the component of along the +y axis.
Mathematics
1 answer:
DochEvi [55]3 years ago
8 0

We have a vector \vec F with a magnitude F of 86.4 N.

a. Let \theta be the angle \vec F makes with the positive x-axis. The x-component of \vec F is

F_x=(86.4\cos\theta)\,\mathrm N

and has a magnitude of 72.3 N, so

72.3=86.4\cos\theta\implies\cos\theta=0.837\implies\theta=\boxed{33.2^\circ}

b. The y-component of \vec F is

F_y=(86.4\cos33.2^\circ)\,\mathrm N=\boxed{47.3\,\mathrm N}

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Answer:

y = 1/2x -3

x=-2 ⇒ y =  -4

x=-1 ⇒ y =  -3.5

x=0 ⇒ y =  -3

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Step-by-step explanation:

Hi, to answer this question we have to isolate y:

x - 2y = 6

-2y =6-x

y = (6-x)/-2

y = -3+1/2x

y = 1/2x -3  

Now, we have to create a table with the next values (see attachment)

x=-2 ⇒ y = 1/2x -3 = 1/2(-2)-3= -4

x=-1 ⇒ y = 1/2x -3 = 1/2(-1)-3= -3.5

x=0 ⇒ y = 1/2x -3 = 1/2(0)-3= -3

x=1 ⇒ y = 1/2x -3 = 1/2(1)-3= -2.5

x=2 ⇒ y = 1/2x -3 = 1/2(2)-3= -2

Feel free to ask for more if needed or if you did not understand something.

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