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2 years ago

A support cable connects the top of a bridge tower to the road below.

Mathematics

1 answer:

levacccp [35]2 years ago

6 0

Answer:

the road is 142 ft away from the center of the bridge tower.

Step-by-step explanation:

Since, the bridge tower is standing vertical to the the road, therefore, the angle made by it is a right angle.

Therefore, the triangle made by cable(hypotenuse) and bridge tower (Perpendicular) on road (base) must be a right angled triangle.

Therefore, by Pythagoras theorem, we have

H² = P²+ B²

P²=H²-B²

P²=(245.9)²-(200.7)²

P=√20186.32=142.07

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Merta reports that 74% of its trains are on time. A check of 60 randomly selected trains shows that 38 of them arrived on time.

kenny6666 [7]

Answer:

No, the on-time rate of 74% is not correct.

Solution:

As per the question:

Sample size, n = 60

The proportion of the population, P' = 74% = 0.74

q' = 1 - 0.74 = 0.26

We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.

Now,

The proportion of the given sample, p = $\frac{38}{60} = 0.634$

Therefore, the probability is given by:

$P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]$

P $(p\leq 0.634) = P[z\leq -1.87188]$

P $(p\leq 0.634) = P[z\leq -1.87] = 0.0298$

Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %

Thus the on-time rate of 74% is incorrect.

6 0

3 years ago

How do I solve the inequality for this: 10 < 9 + x

Firlakuza [10]

Subtract 9 from each side of the equation. so you would get 1<x. meaning that any number larger then 1 would correctly solve the equation.

4 0

3 years ago

Read 2 more answers

The combined area of two squares is 17 square meters. the size of the larger Square are four times as long as the size of the sm

7nadin3 [17]

we are given that ,

The combined area of two squares is 17 square meters.

Area of square= $(side)^2$

Let the side length of smaller square be x

The size of the larger Square are four times as long as the size of the smaller square

$Area \ of \ smaller \ square \ =x^2$

So Area of larger square= $4x^2$

The combined Area is 17 square meter.

$x^2+4x^2=17\\\\5x^2=17\\\\x=\sqrt{\frac{17}{5}}$

Hence the smaller square has the side length= $\sqrt{\frac{17}{5}}$

So the larger square has side length= $2\sqrt{\frac{17}{5}}$

5 0

3 years ago

A population of 1,750 cheetahs decreases by 10% per year. How many cheetahs will there be in the population after 11 years? Roun

Triss [41]

Answer:

The answer is C. 546.

If a population decreases by 11%, that means that 89% (100% - 11% = 89%) of cheetahs remains each number. 89% can be expressed as 0.89, so to calculate the change of the population, we must each year multiply the number of cheetahs by 0.89.

After 1 year: 1750 * 0.89 ≈ 1558

After 2 years: 1558 * 0.89 ≈ 1387

After 3 years: 1387 * 0.89 ≈ 1234

After 4 years: 1234 * 0.89 ≈ 1098

After 5 years: 1098 * 0.89 ≈ 977

After 6 years: 977 * 0.89 ≈ 870

After 7 years: 870 * 0.89 ≈ 774

After 8 years: 774 * 0.89 ≈ 689

After 9 years: 689 * 0.89 ≈ 613

After 10 years: 613 * 0.89 ≈ 546

Step-by-step explanation:

4 0

3 years ago

What is 60/d when d=10

erastova [34]

It is 6 60 divided by 10 is 6

3 0

3 years ago

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