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2 years ago

A support cable connects the top of a bridge tower to the road below.

Mathematics

1 answer:

levacccp [35]2 years ago

6 0

Answer:

the road is 142 ft away from the center of the bridge tower.

Step-by-step explanation:

Since, the bridge tower is standing vertical to the the road, therefore, the angle made by it is a right angle.

Therefore, the triangle made by cable(hypotenuse) and bridge tower (Perpendicular) on road (base) must be a right angled triangle.

Therefore, by Pythagoras theorem, we have

H² = P²+ B²

P²=H²-B²

P²=(245.9)²-(200.7)²

P=√20186.32=142.07

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The answer to -2y-10+2x=0 is 1

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Answer:

the scale factor is the vertical expansion factor.

Step-by-step explanation:

The scale factor of 2 in

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_____

Additional comment

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3 years ago

Identify the probability to the nearest hundredth that a point chosen randomly inside the rectangle is in the square. Only answe

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Answer:

$0.07$

Step-by-step explanation:

we know that

The probability that a point chosen randomly inside the rectangle is in the square is equal to divide the area of the square by the area of rectangle

Let

x-----> the area of square

y----> the area of rectangle

P -----> the probability

$P=\frac{x}{y}$

Find the area of square (x)

$A=5^{2}=25\ in^{2}$

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3 years ago

What is the slope of the line that contains these points? x 31 36 41 46 y 10 8 6 4

ankoles [38]

Answer:

-2/5

Step-by-step explanation:

The slope of the line can be found by

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= (8-10)/(36-31)

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3 years ago

Which of the following equations represents the perpendicular bisector of WX graphed below?

kotykmax [81]

The coordinates of the 2 given points are W(-5, 2), and X(5, -4).

First, we find the midpoint M using the midpoint formula:

$\displaystyle{ M_{WX}= (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )= (\frac{-5+5}{2}, \frac{2+(-4)}{2} )=(0, -1).$

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if m and n are the slopes of 2 parallel lines, then mn=-1.

The slope of WX is $\displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{2-(-4)}{-5-5}= \frac{6}{-10}= -\frac{3}{5}$ .

Thus, the slope n of the perpendicular line is $\displaystyle{ \frac{5}{3}$ .

The equation of the line with slope $\displaystyle{ n= \frac{5}{3}$ containing the point M(0, -1) is given by:

$\displaystyle{ y-(-1)=\frac{5}{3}(x-0)$

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$\displaystyle{ 5x-3y-3=0$

Answer: 5x-3y-3=0

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3 years ago