3 years ago

Can you help me with question 6 please

Mathematics

1 answer:

Licemer1 [7]3 years ago

4 0

I'm pretty sure the answer is 24

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Incomes in a certain town are strongly right-skewed with mean $36,000 and standard deviation $7000. a random sample of 75 househ

Svet_ta [14]

Since the sample is greater than 10, we can approximate this binomial problem with a normal distribution.

First, calculate the z-score:

z = (x - μ) / σ = (37000 - 36000) / 7000 = 0.143

The probability P(x > 37000$) = 1 - P(x < 37000$),
therefore we need to look up at a normal distribution table in order to find
P(z < 0.143) = 0.55567
And
P(x > 37000$) = 1 - 0.55567 = 0.44433

Hence, there is a 44.4% probability that the sample mean is greater than $37,000.

4 0

4 years ago

I don’t quite understand this problem could someone help me please

ale4655 [162]

Answer:

$\frac{7\sqrt{65}}{65}$