Answer:
y = 11(x -1) +6
Step-by-step explanation:
The slope at the given point is ...
y' = 14x -3x^2 = 14(1) -3(1^2) = 11
Then the point-slope equation for the line can be written as ...
y = m(x -h) +k . . . . . . for slope m at point (h, k)
y = 11(x -1) +6
Answer:
Graph G
Step-by-step explanation:
The graphs are attached
Given that the oil-well contractor drills a shaft 7 meters deeper into the ground every 2 hours, hence the rate at which the shaft drills = 7 meter / 2 hours = 3.5 meters per hour
Since the drill goes into the ground, hence the rate is negative that is -3.5 meters per secong
The slope (rate of change) of a line (m) is given by:
a) For graph F, the line passes through the point (0,0) and (10, -20). Hence:
b) For graph G, the line passes through the point (0,0) and (10, -70). Hence:
c) For graph H, the line passes through the point (0,0) and (10, -35). Hence:
d) For graph J, the line passes through the point (0,-3.5) and (10, -3.5). Hence:
