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seraphim [82]
4 years ago
11

Robert is lying on the ground, looking at the top of a flagpole. The angle of elevation to the top of the flagpole is 25°. What

is the height of the flagpole if the distance from his eyes at the ground to the base of the flagpole is 200 ft? PLEASE HELPPPPPP
Mathematics
1 answer:
enyata [817]4 years ago
8 0

Answer: r =15 degrees

Step-by-step explanation:

Measure the length of the shadow of the yardstick and the flagpole. Since the ends of the shadows are in line with the tops of the respective objects and the sun, the lengths of their shadows are proportional. Multiply the shadow ratio by the height of the yardstick (yh) to get the height of the flagpole.

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1450.67

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V=a^2 x h/3

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A ________ is the complete collection of all measurements or data collected, whereas, a ________ is a subcollection of members s
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Answer: Population and sample

Step-by-step explanation:

A population is the complete collection of all measurements or data collected, whereas, a sample is a subcollection of members selected from the complete collection

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Problems 27: the number X is the number of car which passed through the
svet-max [94.6K]

Answer:

a) The value of a= 0.59

b)  The probability that there are at-least 3 cars passing through the stop sign

P(x>3)  = 0.03

c)

The Expected value of X  = 0.62

d)

 The variance of X is   σ² = 0.9556

e)

The standard deviation of X

                                    σ = 0.9775

Step-by-step explanation:

<u><em></em></u>

Given data

X       :      0         1          2            3        4          5

P(x)   :    a       0.30     0.05    0.03    0.02     0.01

a)

      ∑ p(x_{i} ) = 1

 a + 0.30+ 0.05+ 0.03+ 0.02+0.01 = 1

 a  + 0.41 = 1

     a  = 1 - 0.41

   <em>  a  = 0.59</em>

b)

<em>  The probability that there are at-least 3 cars passing through the stop sign</em>

<em>P(x >3)  = P( x=4) + P( x=5)</em>

           =   0.02 +0.01

          = 0.03

c)

X       :      0           1          2            3        4          5

P(x)   :      0.59      0.30     0.05    0.03    0.02     0.01

The Expected value of X

E(X) = ∑ x P(X= x)

      =  0 + 1 ×0.30 + 2×0.05 + 3×0.03 + 4×0.02 + 5×0.01

     =   0.30 + 0.1 + 0.09 +0.08 +0.05

    =  0.62

<em>The Expected value of X </em>

<em>                           E(X)  = 0.62</em>

<em>d) </em>

   The variance of the discrete distribution

       σ² =   ∑ x²p(x) -μ²

      σ² =   0 + 1² ×0.30 + 2² ×0.05 + 3² ×0.03 + 4² ×0.02 + 5²× 0.01 - (0.62)²

          =   1.34 - 0.3844

         = 0.9556

      σ² = √0.9556

<em>e) The standard deviation of the  discrete distribution</em>

<em>      σ = 0.9775</em>

<em></em>

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Up

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