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lys-0071 [83]
3 years ago
7

Are these triangles congruent ?

Mathematics
2 answers:
Vadim26 [7]3 years ago
7 0

Answer:no

Step-by-step explanation:

Andrews [41]3 years ago
5 0
Nope, the corresponding angles are different degrees
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Solve for X please and thank you
notsponge [240]

Answer:

x = 48

Step-by-step explanation:

Given a secant and a tangent from an external point to the circle, then

the product of the external part and the entire secant is equal to the square of the measure of the tangent , that is

2(2 + x) = 10² = 100 ( divide both sides by 2 )

2 + x = 50 ( subtract 2 from both sides )

x = 48

4 0
2 years ago
Anna made 400 quarts of lemonade. She poured the lemonade into containers. Each container holds 4/7 of a quart. How many contain
julsineya [31]
400÷4/7=700
you want divide the totals amount of lemonade among pitchers that only hold 4/7 of the lemonade. if the container held 1 qt, you would divide the total by 1
4 0
3 years ago
Read 2 more answers
For the real-valued functions, find the composition and specify its domain using interval notation.
Helen [10]

Answer:

Composition:   f(x)\,^o\,h(x)=4\,\sqrt{x+4} -1

Domain = { x\,/\,x\geq \,-4  }

Step-by-step explanation:

Given

f(x)=4\,x-1\,\,\, and \,\,\, h(x)=\sqrt{x+4}

The requested composition becomes:

f(x)\,^o\,h(x)=f(h(x))\\f(x)\,^o\,h(x)=f(\sqrt{x+4} )\\f(x)\,^o\,h(x)=4\,\sqrt{x+4} -1

Then the Domain consists of all Real x-values for which the function is defined. In this case, the function is defined for all x-values for which the square root is defined, that is all x values for which:

x+4\geq \,0  (so the square root is defined in the Real number system)

This means x\geq \,-4

The Domain is then all the Real x-values such that x\geq \,-4

6 0
3 years ago
Example
castortr0y [4]

Answer:

6/8

Step-by-step explanation:

y^1-y^2/x^1-x^2

2+4/2+6

6/8

5 0
3 years ago
Read 2 more answers
Drag the labels to the correct locations on the table. Not all labels will be used.
luda_lava [24]

For f(x) = cos(x) we have:

  • midline = 0
  • amplitude = 1
  • period = 2π
  • graph = bottom graph on the second image.

<h3>What are the midline, amplitude, period, and graph of the function f(x)=cos(x)?</h3>

For a general cosine function, we have:

f(x) = A*cos(kx + p) + M

Where:

  • A is the amplitude.
  • k is the frequency.
  • p is the phase.
  • M is the midline.

For the function:

f(x) = cos(x).

We can see that:

A = 1, M = 0, k = 1, p = 0.

So, the amplitude is equal to 1, and the midline is equal to zero.

Now we also need to get the period. By definition of the trigonometric functions sin(x) and cos(x), we know that the period of the two is equal to 2π.

Finally, we need to identify the graph of cos(x).

Notice that:

f(0) = cos(0) = 1.

So the graph of f(x) = cos(x) is the graph with an y-intercept equal to 1. Which is the bottom graph on the second image.

If you want to learn more about cosine functions:

brainly.com/question/17075439

#SPJ1

8 0
2 years ago
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