Answer:
The answer is "26179.4".
Step-by-step explanation:
Assume year 2000 as t, that is t =0.
Formula:

Where,

for doubling time,


Given value:



when year is 2000, t=0 so, year is 2100 year as t = 100.

The answer would be
area = base x height divided by 2
3*0.6 = 1.8/2=0.9 square meters