Which is the graph of the equation 49x^2 - 16y^2 = 784
1 answer:
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Answer:
<h2><em><u>18</u></em></h2>Step-by-step explanation:
<em><u>Given</u></em><em><u>, </u></em>
Radius of the cylinder = 3cm
Height of the cylinder = 3cm
<em><u>Therefore</u></em><em><u>, </u></em>
Lateral surface area of the cylinder
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>The</u></em><em><u> </u></em><em><u>required</u></em><em><u> </u></em><em><u>value</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>green</u></em><em><u> </u></em><em><u>box</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>18</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
Answer:
The length of segment QM' = 6
Step-by-step explanation:
Given:
Q is the center of dilation
Pre-image (original image) = segment LM
New image = segment L'M'
The length of LQ = 4
The length of QM = 3
The length of LL' = 4
The original image was dilated with scale factor = 2
QM' = ?
To determine segment QM', first we would draw the diagram obtained from the given information.
Find attached the diagram
When a figure is dilated, we would have similar shape in thus cars similar triangles.
Segment L'M' = scale factor × length of LM
Let LM = x
L'M' = 2x
Using similar triangles theorem, ratio of their corresponding sides are equal.
QM/LM = QM'/L'M'
3/x = QM'/2x
6x = QM' × x
Q'M' = 6
The length of segment QM' = 6
