HELP PLEASE Jackson sells lemonade for $2 per cup. he paid $20 for supplies to sell 5 cups. What is the domain for this scenario
Answer:
Part A: Histogram :)
Part B: Described below! :)
Step-by-step explanation:
Part A:
A histogram is the best choice because it can show the numbers for multiple categories in a quick and easy manner :)
Part B:
The x axis will have the categories of quiz scores! The y axis will show how many students got that score.
We then put the categories from smallest to largest along the x axis. We will also put the numbers that go with the categories above the category!
Done! you have made your histogram!
Have an amazing day!!
Please rate and mark brainliest!!
Answer: well this is hard
Step-by-step explanation:
First of all you’re adding 7Y and you’re getting -8 and for subtracting you subtract 5why and you’re getting negative one so technically you’re getting different answers?
Answer:
i believe is c
Step-by-step explanation:
because you addd 10 plus 8 times 6.
Answer:
(a)77.4bpm
(b)Mean of Sample 1 = 70.3 beats per minute.
Mean pulse of sample 2 = 70 beats per minute.
(c)
- The mean pulse rate of sample 1 underestimates the population mean.
- The mean pulse rate of sample 2 underestimates the population mean.
Step-by-step explanation:
(a)Population mean pulse.
The pulse of the nine students which represent the population are:
- Perpectual Bempah 64
- Megan Brooks 77
- Jeff Honeycutt 89
- Clarice Jefferson 69
- Crystal Kurtenbach 89
- Janette Lantka 65
- Kevin McCarthy 88
- Tammy Ohm 69
- Kathy Wojdya 87

The population mean pulse is approximately 77.4 beats per minute.
(b)Sample 1: {Janette,Clarice,Megan}
- Janette: 65bpm
- Clarice: 69bpm
- Megan: 77bpm
Mean of Sample 1

Sample 2: {Janette,Clarice,Megan}
- Perpetual: 64bpm
- Clarice: 69bpm
- Megan: 77bpm
Mean of Sample 2

The mean pulse of sample 1 is approximately 70.3 beats per minute.
The mean pulse of sample 2 is approximately 70 beats per minute.
(c)
- The mean pulse rate of sample 1 underestimates the population mean.
- The mean pulse rate of sample 2 underestimates the population mean.