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kozerog [31]
3 years ago
6

A linear function is graphed below.

Mathematics
2 answers:
AnnyKZ [126]3 years ago
8 0

Answer:

Step-by-step explanation:

find the slope m  by using the slope formula

m = (y2 - y1) / (x2 - x1)

Point1 = ( -1,4)  where it takes the form (x1,y1)

Point2 =(5, -5) where it takes the form (x2,y2)

notice the form is important

m = (-5 -4) / (5 - (-1))

m = -9  /  ( 5 +1 )

m = -9 / 6

m = - 3/2

Evgen [1.6K]3 years ago
4 0

Answer:

-1\frac{1}{2}

Step-by-step explanation:

We have two coordinate points and are asked to find a slope.

When finding slope, we can use the formula listed :

\frac{y^2-y^1}{x^2-x^1}}

To understand what the variables are, you can take this :

(x^1,y^1)

(x^2,y^2)

Substitute the points :

(-1,4)

(5,-5)

Now substitute it into the formula :

\frac{-5-4}{5-(-1)}

\frac{-3}{2}

-1\frac{1}{2}

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given three points of a quadratic function find the equation that defines the function (-2,20)(0,-2)(1,-4) hurry please!!​
kotykmax [81]

Answer:

D: y = 3x² - 5x - 2

Step-by-step explanation:

The general form of a quadratic equation is: y = ax² + bx + c    

c is the y-intercept

We are given the point (0, -2) which is the y-intercept, so we can rewrite our general form into

y = ax² + bx - 2

We can create a system of equations to solve for a and b.  We are given two points.  

Equation 1:  Take the first point (-2, 20) and plug it into our general equation...

20 = a(-2)² + b(-2) - 2

   20 = 4a - 2b - 2

        22 = 4a - 2b         (add 2 to both sides)

           11 = 2a - b         (divide both sides by 2 since every coefficient is even)

Equation 2:   Take the point (1, -4) and plug it into the general equation

-4 = a(1)² + b(1) - 2

  -4 = a + b - 2

     -2 = a + b

Now we have our 2 equations:

11 = 2a - b

-2 = a + b

Since the coefficients of b are already have opposite signs, add the two equations together (elimination method)

Now we have

9 = 3a       now solve for a...

 3 = a   (divide by 3 on both sides)

If a = 3, then

-2 = 3 + b

    -5 = b

Our equation is

y = 3x² - 5x - 2

6 0
3 years ago
Look at the attachment<br>Simplified it too <br>pls take it seriously ​
Phantasy [73]

\\ \rm\rightarrowtail \dfrac{sin(180+A)+2cos(180+A).cos(A-180)}{2cos^2(360+A)-cos(-A)}

\\ \rm\rightarrowtail \dfrac{-sinA+2(cos^2A-sin^2A)}{2cos^2A-cosA}

\\ \rm\rightarrowtail \dfrac{-sinA+2cos^2A-2sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA+2-2sin^2A-2sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA-4sin^2A}{cosA(2cosA-1)}

\\ \rm\rightarrowtail \dfrac{-sinA(4sinA-1)}{cosA(2cosA-1)}

\\ \rm\rightarrowtail -tanA\left(\dfrac{4sinA-1}{2cosA-1}\right)

5 0
2 years ago
May someone please help me find three ordered pairs so I can graph on the coordinate plane please you get five stars and things
adell [148]

Answer:

the answer for x-y=(-2) is x=y−2 the answer for x-y=2 is x=2+y

Step-by-step explanation:

hope this helps if not let me know

8 0
2 years ago
1) What is the shape of the graph of the following parametric equations?
yuradex [85]

Answer:

The shape of the graph of the parametric equations given is:

  • <u>B. ellipse</u>.

Step-by-step explanation:

By inserting each of the equations given in a graphing calculator (Annex 1), it can be identified that both the first and second equations have an elliptical or ellipse shape, which is characterized by being periodic in the two directions in which it runs. Thus, the equation x = 3 cos t runs with elliptical motion on the Y-axis of the Cartesian plane, while the equation y = 2 without t + 1 runs with elliptical motion on the X-axis.

7 0
4 years ago
CAN YALL pLZ HELP ME
Mamont248 [21]
The answer is B because facts
3 0
3 years ago
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