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The answer is on the picture below
Answer:
5n + 10d represented the money spend by the Amy in playing board games of cost $5 and $10 .
Step-by-step explanation:
As given
Amy and Mary are playing a board game that uses game money if $5 and $10.
At the end of the game, Amy has n bills worth $5 each and d bills worth $10 each .
Total amount of n bills = 5n
Total amount of d bills = 10d
Thus
Total money spend by the Amy in playing board games = Total amount of n bills + Total amount of d bills
= 5n + 10d
Therefore 5n + 10d represented the money spend by the Amy in playing board games of cost $5 and $10 .
Answer:
db / dt = kb
this becomes b(t) = Ce^(kt)
C = 100, the initial population
P(1) = 420 = 100 e^(1k)
4.2 = e^k
ln 4.2 = k
a) thus, b(t) = 100 e^(t ln 4.2)
b) b(3) = 100 e^(3 ln 4.2)
c) growth constant will still be ln 4.2 (constant percentage of populatioin)
d) 10000 = 100 e^(t ln 4.2)
100 = e^(t ln 4.2)
ln 100 = t ln 4.2
t = ln 100 / ln 4.2
Step-by-step explanation:
Answer:
The bill size can be considered usual.
Step-by-step explanation:
Mean (μ) = $108.43
Standard deviation (σ) = $36.98
Now, consider the distribution to be normal distribution :
Now, finding values of z-score from the table. We get,
P(Z > 1.75) = 0.9599
⇒ 95.99%
So, only 4.01 % of the people in the city wastes water.
Hence, the bill size can be considered usual.
