Answer:
time = 1secs
<em>Max height = 25metres</em>
Step-by-step explanation:
Let the equation that models the height of the ball be expressed as;
h(t) = −16t^2 + 32t + 9
t is the time in seconds
The velocity of the ball at its maximum height is zero i.e dh/dt = 0
dh/dt = -32t + 32
0 = -32t + 32
32t = 32
t = 32/32
t = 1 seconds
The ball will reach its maximum height after 1 seconds.
Get the maximum height reached. Substitute t = 1 into the modeled function;
h(t) = −16t^2 + 32t + 9
h(1) = −16(1)^2 + 32(1) + 9
h(1) = −16 + 32 + 9
h(1)= 16+9
<em>h(1) = 25</em>
<em>Hence the maximum height reached is 25metres</em>
It depends on the total of how long the race took, but each girl ran 1/4 of the race so if you know the total time just divide the time by 4 and you will get the answer. If you don't just say each girl ran 1/4 of the time.
The answer would be 0.3635
Answer:
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Step-by-step explanation:
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