The volume of the solid of revolution is approximately 37439.394 cubic units.
<h3>
How to find the solid of revolution enclosed by two functions</h3>
Let be 
and 
, whose points of intersection are 
, 
, respectively. The formula for the solid of revolution generated about the y-axis is:
(1)
Now we proceed to solve the integral: 
(2)
![V = 6\pi \left[(y-1)\cdot \ln y\right]\right|_{1}^{e^{35/6}}](https://tex.z-dn.net/?f=V%20%3D%206%5Cpi%20%5Cleft%5B%28y-1%29%5Ccdot%20%5Cln%20y%5Cright%5D%5Cright%7C_%7B1%7D%5E%7Be%5E%7B35%2F6%7D%7D)
![V = 6\pi \cdot \left[(e^{35/6}-1)\cdot \left(\frac{35}{6} \right)-(1-1)\cdot 0\right]](https://tex.z-dn.net/?f=V%20%3D%206%5Cpi%20%5Ccdot%20%5Cleft%5B%28e%5E%7B35%2F6%7D-1%29%5Ccdot%20%5Cleft%28%5Cfrac%7B35%7D%7B6%7D%20%5Cright%29-%281-1%29%5Ccdot%200%5Cright%5D)
The volume of the solid of revolution is approximately 37439.394 cubic units. 
To learn more on solids of revolution, we kindly invite to check this verified question: brainly.com/question/338504
B is the answer to the question
Answer:
10=60 5=30
Step-by-step explanation:
Let x represent the first even integer: x = 2(k) → y = 2k
Let y represent the second even integer: y = 2(k + 1) → y = 2k + 2
x · y = 48
(2k) · (2k + 2) = 48
4k² + 4k - 48 = 0
4(k² + k - 12) = 0
4 (k + 3)(k - 2) = 0
k = -3, k = 2 (Note: POSITIVE integers so k = -3 is ruled out)
x = 2k → x = 2(2) → x = 4
y = 2(k + 1) → y = 2(2 + 1) → y = 2(3) → y = 6
The smaller number (x) is 4
