Answer:
-2
Step-by-step explanation:
Absolute value is the distance from a number to 0 on the number line, so the number can't be negative, only positive. The absolute value of -1 would be 1, therefore it couldn't be -2, or any other negative numbers.
X - 42 is a straight vertical line passing through -42 on the x-axis ( point -42,0)
so the slope is infinite .
Another line with same slope and parallel to it would be x = 36.
A horizontal like with slope 0 is perpendicular to it It would have equation y any number so y = 6 would be an example.
Answer:
Most people found the probability of just stopping at the first light and the probability of just stopping at the second light and added them together. I'm just going to show another valid way to solve this problem. You can solve these kinds of problems whichever way you prefer.
There are three possibilities we need to consider:
Being stopped at both lights
Being stopped at neither light
Being stopped at exactly one light
The sum of the probabilities of all of the events has to be 1 because there is a 100% chance that one of these possibilities has to occur, so the probability of being stopped at exactly one light is 1 minus the probability of being stopped at both lights minus the probability of being stopped at neither.
Because the lights are independent, the probability of being stopped at both lights is just the probability of being stopped at the first light times the probability of being stopped at the second light. (0.4)(0.7) = 0.28
The probability of being stopped at neither is the probability of not being stopped at the first light, which is 1-0.4 or 0.6, times the probability of not being stopped at the second light, which is 1-0.7 or 0.3. (0.6)(0.3) = 0.18
The probability at being stopped at exactly one light is 1-0.18-0.28=.54 or 54%.
Answer:
± 2
Step-by-step explanation:
let the number be n , then
n² - 4 = 0 ( add 4 to both sides )
n² = 4 ( take square root of both sides )
n = ±
= ± 2
The number is - 2 or 2
Answer: 1) D
2) C
Step-by-step explanation:
1. The blue algae has an initial mass of 20 kg and doubles its mass every hour. Then after t hours, the mass of blue algae is
2. The green algae has an initial mass of 160 kg and grows at a constant rate of 0.20 kg per minute. Then after t hours (60t minutes), the mass of green algae is
Part I) At t=3:
The mass of green algae has 196-160=36 kg more mass at 3 hours.
Part II) At t=4:
The blue algae has 320-208=112 kg more mass at 4 hours.