A kilogram of silver contains 5.58×10²⁴ atoms.
<h3>How to determine the parameter</h3>
From the question given above, the following data were obtained:
- 1 mole of silver = 107.9 g
- Number of atoms in 1 mole of silver = 6.02×10²³ atoms.
- Number of atoms in a kilogram of silver is unknown
Now, we shall convert 1 kg of silver to grams (g).
This can be obtained as follow:
1 kg = 1000g
Therefore, 1 kg of silver is equivalent to 1000g.
Now, let's determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:
If 107.9 g of silver contains 6.02×10²³ atoms.
Then, 1000 g of silver will contain:
= (1000 × 6.02×10²³) / 107.9
= 5.58×10²⁴ atoms.
Thus, a kilogram of silver contains 5.58×10²⁴ atoms.
Learn more about atoms here:
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Answer:
The first option: -5/4x + 1/6.
Step-by-step explanation:
(3/4x - 2/3) - (-5/6 + 2x)
= (3/4x - 2/3) + 5/6 - 2x
= 3/4x - 2x - 2/3 + 5/6
= 3/4x - 8/4x - 4/6 + 5/6
= -5/4x + 1/6
So, the first option: -5/4x + 1/6.
Hope this helps!
Answer:
0.01133786848
Step-by-step explanation:
Y = 3x + 1
Parallel lines have the same slope so the slope would be 3. Take the given equation and add the 3x to the other side. Using the given point. -2 (y point) = 3(-1(x point)) + b. Solve for b by adding the 3 over. b = 1 which is your y intercept.
