If m ACD = 30 => m DCB = 60.
In triangle ACD:
AC^{2}+CB^{2}=AB^{2} => AB=
=32.
=> P=16+32+
=48 +.
In triangle ACD:
AC^{2}+CB^{2}=AB^{2} => AB=
=> P=16+32+
Round 387,828 to the nearest ten thousand
2 answers:
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Answer:
x=19
Step-by-step explanation:
First, you place the numbers in place of the variables in their relative positions using the pythagorean theorem:
Then you square the numbers that you currently have:
Then subtract 225 from both sides to isolate the x:
This gives you the equation:
Then take the square root of both sides which gives you:
Then round to the nearest whole number which gives you x=19