Question

100 Points! Question Urgent!!!!!!

Answer 1

Answer:

9

Step-by-step explanation:

→You can use the Pythagorean Theorem to solve this, by plugging in the numbers, like so:

$a^2+b^2=c^2\\x^2+(x-3)^2=(x+3)^2$

$x^2+x^2-6x+9=x^2+6x+9$

→Subtract $x^2-6x+9$ from both sides:

$x^2 = 12x$

→Subtract 12x from both sides:

$x^2 -12x=0$

→Factor out x:

$x(x-12)=0$

→Separate, set = to 0, and solve:

$x = 0\\x -12=0$        →      Add 12 to both sides:        $x = 12$

→So we have 0 and 12, as our answers. However, we cannot have 0 as a side length, since this would not be possible.

→All we need to do is take 12, and plug it into the equation for the shortest leg.

$x - 3=?\\12-3=9$