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larisa [96]
3 years ago
15

The manufacturer of a certain brand of aluminum foil claims that the amount of foil on each roll follows a Normal distribution w

ith a mean of 250 square feet (ft^2) and a standard deviation of 2 ft^2 . To test this claim, a restaurant randomly selects 10 rolls of this aluminum foil and carefully measures the mean area to be ¯ = 249.6 ft2 .
Find the probability that the sample mean area is 249.6 ft^2 or less if the manufacturer’s claim is true.


0.4207


0.0228


0.5793


0.7364


0.2636
Mathematics
1 answer:
natali 33 [55]3 years ago
5 0

Answer: 0.4207

Step-by-step explanation:

Let \overline{x} be the sample mean area.

Given: Population mean : \mu=250 sq. feet

Standard deviation: \sigma=2 sq. feet

Sample size : n= 10

The probability that the sample mean area is 249.6 \text{ ft}^2 or less if the manufacturer’s claim is true.

P(\overline{x}

Required probability = 0.4207

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