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larisa [96]
3 years ago
15

The manufacturer of a certain brand of aluminum foil claims that the amount of foil on each roll follows a Normal distribution w

ith a mean of 250 square feet (ft^2) and a standard deviation of 2 ft^2 . To test this claim, a restaurant randomly selects 10 rolls of this aluminum foil and carefully measures the mean area to be ¯ = 249.6 ft2 .
Find the probability that the sample mean area is 249.6 ft^2 or less if the manufacturer’s claim is true.


0.4207


0.0228


0.5793


0.7364


0.2636
Mathematics
1 answer:
natali 33 [55]3 years ago
5 0

Answer: 0.4207

Step-by-step explanation:

Let \overline{x} be the sample mean area.

Given: Population mean : \mu=250 sq. feet

Standard deviation: \sigma=2 sq. feet

Sample size : n= 10

The probability that the sample mean area is 249.6 \text{ ft}^2 or less if the manufacturer’s claim is true.

P(\overline{x}

Required probability = 0.4207

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3 years ago
According to data from a medical​ association, the rate of change in the number of hospital outpatient​ visits, in​ millions, in
GaryK [48]

Answer:

a) f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) f(t=2015) = 264,034,317.7

Step-by-step explanation:

The rate of change in the number of hospital outpatient​ visits, in​ millions, is given by:

f'(t)=0.001155t(t-1980)^{0.5}

a) To find the function f(t) you integrate f(t):

\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt

To solve the integral you use:

\int udv=uv-\int vdu\\\\u=t\\\\du=dt\\\\dv=(t-1980)^{1/2}dt\\\\v=\frac{2}{3}(t-1980)^{3/2}

Next, you replace in the integral:

\int t(t-1980)^{1/2}=t(\frac{2}{3}(t-1980)^{3/2})- \frac{2}{3}\int(t-1980)^{3/2}dt\\\\= \frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}+C

Then, the function f(t) is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'

The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient​ visits.

Hence C' = 264,034,000

The function is:

f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000

b) For t = 2015 you have:

f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7

3 0
3 years ago
3) A Jewelry artist charges $7.00 for each pair of earrings she sells. in 3 hours, she sells 15 pairs of
Alex787 [66]

Answer: $175

Step-by-step explanation:

$7.00 x 15 = $105.00

$105.00 / 3 hours = $35/hr.

$35 x 5 = $175

6 0
2 years ago
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