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BigorU [14]
3 years ago
6

Need help on this pleaseeeeee!

Mathematics
1 answer:
crimeas [40]3 years ago
4 0
This triangle is a Scalene Triangle because all the sides are unequal!
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Evaluate and simplify the following complex fraction.
Naya [18.7K]

Answer:

-10/7

Step-by-step explanation:

(-5/7)/(2/4) = (-5/7)/(1/2) = (-5/7)*(2/1) = -10/7

3 0
3 years ago
Which of the following shows that ABCD is a parallelogram for x=6 and y =8? (20 points)
Reika [66]

Answer:

AB = CD = 44 and BC = AD = 31 ; so ABCD is a parallelogram

Step-by-step explanation:

A parallelogram should have two pairs of parallel sides meaning the length of side AB should be the same as the length of side CD and the length of side AD should be the same as the length of side BC.

<u>First, lets see if line AB is parallel to line CD.</u>

Let's start by finding out the length of line AB.

Since we know x = 6 we will replace x with 6 in the expression:

7(6) + 2 = 42 + 2 = 44

Now that we know the length of line AB is 44, lets find the length of line CD by replacing x with its value of 6:

9(6) - 10 = 54 - 10 = 44

Now that we know the length of line CD is 44, we can see that line AB is parallel to line CD since they both have the same length of 44.

<u>Now, lets see if line BC is parallel to line AD.</u>

Let's start by finding out the length of line BC.

Since we know y = 8 we will replace y with 8 in the expression:

3(8) + 7 = 24 + 7 = 31

Now that we know the length of line BC is 31, lets find the length of line AD by replacing y with its value of 8:

5(8) - 9 = 40 - 9 = 31

Now that we know the length of line AD is 31, we can see that line BC is parallel to line AD since they both have the same length of 31.

<u>Conclusion</u>

ABCD is a parallelogram because it contains two parallel sides.

5 0
3 years ago
(-3y3-5y-2)+(-7y2+5y+2)
Slav-nsk [51]

Answer:

=-23y

Step-by-step explanation:

(-3y3-5y-2)+(-7y2+5y+2)

=-3yX3-5y-2-7yX2+5y+2

=-3X3y-5y-7X2y+5y-2+2

=-3X3y-7X2y-2+2

=-9y-7X2y-2+2

=-9y-14y-2+2

=-23y-2+2

=-23y

I hope this helps!

4 0
3 years ago
Read 2 more answers
If a parabola had a y-intercept of (0,5) and an axis of symmetry at x = 4, what other point must be on the graph? (hint: draw)
Serga [27]

Answer:

(8, 5)

Step-by-step explanation:

Let's take a look at the y-intercept, (0, 5).  If the axis of symmetry is x = 4, then the distance from (0, 5) is 4 units.  If we reflect this point (0, 5) about the axis of symmetry x = 4, the resulting point is (8, 5).  In other words, the distance from the y-intercept to the axis of symmetry is 4 units, and so the distance from the y-intercept must be 4 units plus 4 units, or 8 units.

The only answer choice that matches this is the second one:  (8, 5).

3 0
3 years ago
Evaluate (–1)8 + (–1)7 – 16 – 14 – (–1)2. Pay attention to the placement of the parentheses and negative signs. Question 1 optio
Inessa05 [86]
Since we are evaluating, we use PEMDAS so we know the order the operations. Follow PEMDAS:

Original Expression: (-1)8+(-1)7-16-14-(-1)2.

Evaluating: -8-7-16-14+2

-8-7=-15-16=-31-14=-45+2=-43.

The answer is -43 according to PEMDAS.
8 0
3 years ago
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