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Agata [3.3K]
3 years ago
9

HELP WHAT PERCENT IS THE SALES TAX????

Mathematics
1 answer:
Juliette [100K]3 years ago
5 0

Answer:

first one is 6 cents(6 percent) second one 14 cents (14%)

Step-by-step explanation:

is just didviding them

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2 and one half cakes are divided up into 18 pieces for guests how much cake will each person get
natali 33 [55]

Well if you were to do 18 ÷ 2 it would be 8. But since this is 8 and a half let's use 2.5. So, let's do this.

18 ÷ 2.5 = 7.2.

But since cake can't be exactly that we can estimate to 7 since it is the closest so, the answer is 7 pieces of cake.

4 0
3 years ago
Find the slope and the y-intercept of the graph of the linear equation y=5/4 x-7
elena55 [62]

Answer: m=-7

y intercept=5/4

Step-by-step explanation:

4 0
3 years ago
Evaluate the integral of 17/(x^(3)-125)
kvv77 [185]
x^3-125=(x-5)(x^2+5x+25)

\dfrac{17}{(x-5)(x^2+5x+25)}=\dfrac a{x-5}+\dfrac{bx+c}{x^2+5x+25}
\dfrac{17}{(x-5)(x^2+5x+25)}=\dfrac{a(x^2+5x+25)+(bx+c)(x-5)}{(x-5)(x^2+5x+25)}
\implies17=(a+b)x^2+(5a-5b+c)x+(25a-5c)
\implies\begin{cases}a+b=0\\5a-5b+c=0\\25a-5c=17\end{cases}\implies a=\dfrac{17}{75},b=-\dfrac{17}{75},c=-\dfrac{34}{15}

\displaystyle\int\dfrac{17}{x^3-125}\,\mathrm dx=\dfrac{17}{75}\int\dfrac{\mathrm dx}{x-5}-\dfrac{17}{75}\int\frac x{x^2+5x+25}\,\mathrm dx-\dfrac{34}{15}\int\dfrac{\mathrm dx}{x^2+5x+25}
\displaystyle=\dfrac{17}{75}\int\dfrac{\mathrm dx}{x-5}-\dfrac{17}{150}\int\frac{2x+5}{x^2+5x+25}\,\mathrm dx-\dfrac{17}{10}\int\dfrac{\mathrm dx}{x^2+5x+25}
\displaystyle=\dfrac{17}{75}\int\dfrac{\mathrm dx}{x-5}-\dfrac{17}{150}\int\frac{2x+5}{x^2+5x+25}\,\mathrm dx-\dfrac{17}{10}\int\dfrac{\mathrm dx}{\left(x+\frac52\right)^2+\frac{75}4}

The first integral is trivial. For the second, replace y=x^2+5x+25 so that \mathrm dy=(2x+5)\,\mathrm dx. For the third, take x+\dfrac52=\dfrac{5\sqrt3}2\tan z so that \mathrm dx=\dfrac{5\sqrt3}2\sec^2z\,\mathrm dz.

\displaystyle=\dfrac{17}{75}\ln|x-5|-\dfrac{17}{150}\int\frac{\mathrm dy}y-\dfrac{17}{10}\int\dfrac{\frac{5\sqrt3}2\sec^2z}{\left(\frac{5\sqrt3}2\tan z\right)^2+\frac{475}4}\,\mathrm dz
\displaystyle=\dfrac{17}{75}\ln|x-5|-\dfrac{17}{150}\ln|y|-\dfrac{17}{25\sqrt3}\int\dfrac{\sec^2z}{\tan^2z+1}\,\mathrm dz
\displaystyle=\dfrac{17}{75}\ln|x-5|-\dfrac{17}{150}\ln(x^2+5x+25)-\dfrac{17}{25\sqrt3}\int\mathrm dz
\displaystyle=\dfrac{17}{75}\ln|x-5|-\dfrac{17}{150}\ln(x^2+5x+25)-\dfrac{17}{25\sqrt3}z+C
\displaystyle=\dfrac{17}{75}\ln|x-5|-\dfrac{17}{150}\ln(x^2+5x+25)-\dfrac{17}{25\sqrt3}\arctan\dfrac{2x+5}{5\sqrt3}+C
8 0
3 years ago
Find the constant of variation when t varies directly as the square of s, and t = 64 when S = 4.
UkoKoshka [18]

Answer:

The constant of variation is 4

Step-by-step explanation:

We are looking for the constant of variation when t varies directly as the square of s

t = k s^2  where k is the constant of variation

t = 64 and s = 4

64 = k  4^2

64 = k * 16

Divide each side by 16

64/16 = k * 16/16

4 = k

The constant of variation is 4

7 0
2 years ago
Solve for the missing side. Round to the nearest tenth.<br> HELP MEEE PLS ):
Bingel [31]

Answer:

b² =  13.2

Step-by-step explanation:

5.8²+b²=14.4²

33.64+b²=207.36

-33.64       -33.65

b²= √173.71

b² = 13.1799089526

b² =  13.2

8 0
3 years ago
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