2/5 of the fish in gary's fish tank are guppies. 1/4 of the guppies are red. What fraction of the fish in Gary's tank are red gu
2 answers:
Answer:
Step-by-step explanation:
Given : 2/5 of the fish in gary's fish tank are guppies.
1/4 of the guppies are red.
To Find : What fraction of the fish in Gary's tank are red guppies?
Solution:
2/5 of the fish in gary's fish tank are guppies.
Out of 2/5 th of the fish in gary's fish tank 1/4 of the guppies are red.
So, The fraction of fish in Gary's tank are red guppies =
=
=
Hence the fish in Gary's tank are red guppies
You might be interested in
Answer:
3<em>x </em>+ 2<em>y</em> = 34. and two possible pairs of positive numbers are (<em>x</em>, <em>y</em>) = (10, 2) and (<em>x</em>, <em>y</em>) = (4, 11).
Step-by-step explanation:
Let the First positive number be <em>x</em> and second positive number be <em>y.</em>
Triple of first number = 3<em>x</em>
double of second number = 2<em>y</em>
According to question,
3<em>x </em>+ 2<em>y</em> = 34
Therefore, the equation is 3<em>x </em>+ 2<em>y</em> = 34
So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34
Now, 3<em>x </em>+ 2<em>y</em> = 34
3<em>x </em>= 34 - 2<em>y</em>
Let x = 10 and by substituting its value in above expression,
Therefore first pair (<em>x</em>, <em>y</em>) = (10, 2)
In the same way put x = 4 then,
3<em>x </em>= 34 - 2<em>y</em>
Therefore first pair (<em>x</em>, <em>y</em>) = (4, 11)
Therefore, (<em>x</em>, <em>y</em>) = (4, 11) and (<em>x</em>, <em>y</em>) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34.