Write your question here (Keep it simple and clear to get the best answer)what is the domain of the function y=✓3-s?

Mathematics

1 answer:

Ilya [14]2 years ago

6 0

Answer: D: s∈ (-∞, 3]

Step-by-step explanation:

When we have a function:

y = f(x)

The domain is the set of the possible values we can input in f(x).

In this case, we have:

y = √(3 - s)

Where our variable is s.

So we want to find the possible values of s we can input in that function.

Remember that if y is a real number, then we can not have a negative number inside the square root, because it will lead to an complex solution.

Then the argument of the square root needs to be equal to or larger than zero.

This means that:

3 - s ≥ 0

From this inequality, we can find the possible values of s, which will be the domain.

We need to isolate s.

3 ≥ s

This means that s needs to be smaller than or equal to 3.

Then the domain is:

D: s∈ (-∞, 3]

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If a town starts with population of 63,500 that declines by 700 people each year, construct an equation to model its population

ankoles [38]

The equation would be 63500-700x=P, where 63500 is the original population, -700 is the amount the population decreases each year, x is the number of years, and P is the total population.

To answer the second part of the question, plug in 53000 for P and solve for x:

63500-700x=53000

<em>*Subtract 63500 from both sides*</em>

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Hope this helps!!

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between 1995 and 2006, the population of samburg, usa(in thousands) can be modeled by f(x) = 0.35x(squared) - 2.1x+15.8 where x=

Juli2301 [7.4K]

$\bf f(x)=0.35x^2-2.1x+15.8\qquad 
\begin{cases}
x=\textit{year since 1995}\\
f(x)=\textit{population amount}
\end{cases}$

the equation is a quadratic one, and it has a positive coefficient on the leading term, meaning, is opening upwards, so it has a "burrow" for the vertex.

the minimum or lowest point for a quadratic opening upwards is, well, the vertex point :), the "x" value is the year, the "y" or f(x) value is the population, we're asked for the year, or the x-coordinate of the vertex

well $\bf \begin{array}{llll}
f(x)=&0.35x^2&-2.1x&+15.8\\
&\quad \uparrow &\quad \uparrow&\uparrow \\
&\quad a&\quad b &c
\end{array}
\\\\

\\\\
\qquad \textit{vertex of a parabola}\\ \quad \\
\qquad 

\left(\boxed{-\cfrac{{{ b}}}{2{{ a}}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$