i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the
Solution:
<u>Note that:</u>
- Area = Base x Height
- Perimeter = Sum of all sides
<u>Finding the area of the parallelogram:</u>
- Area = Base x Height
- => Area = 9.2 x 3.8
- => Area = 34.96 cm²
<u>Finding the perimeter of the parallelogram:</u>
- Perimeter = Sum of all sides
- => Perimeter = 2(4.1) + 2(9.2)
- => Perimeter = 26.6 cm
Correct option is D.
Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.
Answer:
B'(- 2, 2 )
Step-by-step explanation:
Given the translation rule (x, y ) → (x + 3, y - 2 )
This means add 3 to the original x- coordinate and subtract 2 from the original y- coordinate, that is
B(- 5, 4 ) → B'(- 5 + 3, 4 - 2 ) → B'(- 2, 2 )
Here youuuu gooo hope this helpsss
