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Bad White [126]
4 years ago
13

Plz help me! No guessing plz!

Computers and Technology
1 answer:
Tomtit [17]4 years ago
4 0
C- World Wide Web - It has all web pages and files delivered by web servers 
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7. A patent is an example of a rare and valuable resource. Indicate whether the statement is true or false and also justify it.
mamaluj [8]

Answer:

True.

Explanation:

Patent can be defined as the exclusive or sole right granted to an inventor by a sovereign authority such as a government, which enables him or her to manufacture, use, or sell an invention for a specific period of time.

Generally, patents are used on innovation for products that are manufactured through the application of various technologies.

Basically, the three (3) main ways to protect an intellectual property is to employ the use of trademarks, copyright and patents.

Hence, a patent is an example of a rare and valuable resource because it protects the intellectual property of an individual or business entity and as such serves as a medium for gaining royalties or valuable economic benefits.

7 0
3 years ago
Amber wants to give her audience copies of her presentation so they can follow along and take notes. What option should Amber ch
blagie [28]

Answer:

Print handouts

Explanation:

I had this question and even if you didn't put the answer options i knew what it was I hope this helped you out (:

6 0
3 years ago
Read 2 more answers
The labor market shows the:
Bad White [126]
<span>The labor market shows the </span><span>supply of available workers in relation to available work. The labor market is made up of </span>people who are working or looking for work. Those who are actively searching for work are calculated in the labor market as well. Those who are able to work but are not searching for work are not part of the labor market. 
8 0
3 years ago
Si la velocidad del sonido en el aire es de 330m/s , calcula la longitud De onda en metros, de una nota musical de frecuencia 55
omeli [17]

Answer: 3/5 or 0.6m

Explanation:

frecuencia (f) = 550Hz

velocidad del sonido en el aire (v) = 330m/s

velocidad =frecuencia × longitud De onda(λ)

v = fλ

330 = 550 × λ

λ = 330 / 550

λ = 3/5

λ = 0.6m

8 0
3 years ago
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scoray [572]
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4 0
3 years ago
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