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777dan777 [17]
3 years ago
15

I need help on number 57.

Mathematics
1 answer:
Art [367]3 years ago
5 0
Multiply all prices by the number of the brand, and then multiply total number of brands by 80, den subtract
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Find all of the zeros of f(x) = 5x^2 +40x-100
Umnica [9.8K]

Answer:the answer is B

Step-by-step explanation:

4 0
3 years ago
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Solve for y<br> 1.02 = -3.6 + 3.9
Crazy boy [7]

Answer:

1344

Step-by-step explanation:

dont listen to me this is wrong

6 0
2 years ago
48 is the product of Carlos's age and 3.
Sergio [31]

Answer:

16

Step-by-step explanation:

48= 3x

48/3 = x

x= 16

'product and' means multiply I googled it

7 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
Can someone please help me
jeka94

Answer:

A. 1200

Step-by-step explanation:

Speed in meter per minute

= (216*1000)/(3*60)

= 216000/180

= 1200

7 0
2 years ago
Read 2 more answers
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