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Cloud [144]
3 years ago
5

One forth of a peperoni pizza has 12 peperonis; how many peperonis are

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0

Answer: 48

Step-by-step explanation:

12*4

since 1/4 of the pizza has 12 pepperonis on it.

dolphi86 [110]3 years ago
6 0

Answer:

48

Step-by-step explanation:

12x4=48

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If f is a continuous function such that the integral from 1 to 4 of f of x, dx equals 10, evaluate the integral from 2 to 8 of 2
IgorLugansk [536]

Answer: 10

Step-by-step explanation:

Since integral from 1 to 4 of f(x) =10

To evaluate integral from 2 to 8 of 2 times f(2x), using substitution method

Let U = 2x, dU = 2dx, dx = dU/2

Evaluate the limit, upper limit gives dU = 2*4 = 8, lower limit gives dU = 2*1 = 2.

Since this limit are the same as the limit for the question,

Therefore, F(4) - F(1) = F(8) - F(2) = 10

Substituting dx=dU/2

Gives,

Integral from 2 to 8 of 2 times f(2x)= (1/2)(2)(F(8)-F(2)) = 10

6 0
3 years ago
At a vehicle dealership 5 cars are sold for 2 trucks. Last year the dealership sold 128 trucks how many cars did they sell?
baherus [9]
The answer should be 64 cars sold at the dealership
7 0
3 years ago
The ratio of two numbers is 4 to 3. The sum of the numbers is 49. What are the two numbers?​
Irina-Kira [14]

Answer:

28/21

Step-by-step explanation:

28/21 is the equivalent to 4/3.

We know this is the fraction we are looking for because 28 + 21 = 49

Hope that helps!

4 0
2 years ago
I need help please!!!
galben [10]

Answer:

Y= 3

Step-by-step explanation:

When the line hits - 1

The y axis shows that its 3

3 0
3 years ago
What are the real and complex solutions of the polynomial equation? x^3-8=0. with imaginary numbers
seraphim [82]

Answer:

Solutions are 2,  -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

or 2,  -1 +  1.58 i  and -1 - 1.58i

(where the last 2 are equal to nearest hundredth).


Step-by-step explanation:

The real solution is x = 2:-

x^3 - 8 = 0

x^3 = 8

x = cube root of 8 = 2

Note that a cubic equation must have  a total of 3 roots ( real and complex in this case).  We can find the 2 complex roots by using the following identity:-

a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here  a = x and b = 2 so we have

(x - 2)(x^2 + 2x + 4) = 0

To find the complex roots we solve x^2 + 2x + 4 = 0:-

Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2

= -1 +/- (sqrt( -10)) / 2

= -1 +  0.5 sqrt10 i  and -1 - 0.5 sqrt10 i

4 0
3 years ago
Read 2 more answers
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