If you don't include the outlier (50) then it is 79.7
Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
i = interest 3% for 30 years
This is a simple dynamical system for whom the the solutions are given as
](https://tex.z-dn.net/?f=S%3DR%5B%5Cfrac%7B%28i%2B1%29%5En-1%7D%7Bi%7D%5D%28i%2B1%29)
putting values we get
S=2000[\frac{(1.03)^{30}-1}{0.03}](1.03)
= $98005.35
withdrawal of money takes place from one year after last payment
To determine the result we use the present value formula of an annuity date

we need to calculate R so putting the values and solving for R we get
R= $6542.2356
At the end of the 6 months the balance would be 360.54