Question

Two airplanes leave an airport at the same time and travel in opposite directions. One plane travels 60km\h slower than the other. If the two planes are 7304 kilometers apart after 4 hours, what is the rate of each plane?

Answer 1

Answer:

4 V + 4 (V - 60) = D    where D is distance apart after 4 hrs

8 V - 240 = 7304

V = 943 km/hr

and V2 = 943 - 60 = 883 km/hr       where second plane is 60 km/hr slower