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2 years ago

Math question area of figure

Mathematics

1 answer:

uysha [10]2 years ago

7 0

Answer:

We divide it into 3 rectangles:

A rectangle with sides 19mi and 5mi,

a rectangle with sides 1mi and 31mi,

and a rectangle with sides 10mi and 20mi,

so we get 95 + 31 + 200 = $\boxed{326}$

Hope this helps!

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Find the midpoint of PQ P(4 1/3, 3 1/6), Q(-2 1/5, 3 2/3)

Paha777 [63]

Answer:

$(1\frac{1}{15},3\frac{5}{12})$

Step-by-step explanation:

To find the midpoint, you must average the x's then average the y's.

So the x's are $4 \frac{1}{3}$ and $-2\frac{1}{5}$ .

The y's are $3\frac{1}{6}$ and $3\frac{2}{3}$ .

To find an average of a data with 2 elements you must add the two elements then take that sum and divide it by 2.

So this is what we will do with the x's then the y's.

So first x:

$\frac{4\frac{1}{3}+-2\frac{1}{5}}{2}$

Write as improper fractions:

$\frac{\frac{13}{3}+\frac{-11}{5}}{2}$

Division by 2 is the same as multiplying by 1/2:

$\frac{13}{6}+\frac{-11}{10}$

The least common multiple of 6 and 10 is 30. We will multiply first fraction by 5/5 and 3/3 for the second so we can have the same denominator.

$\frac{65}{30}+\frac{-33}{30}$

Now that the bottoms are the same we can write as one fraction:

$\frac{65+-33}{30}$

Simplify:

$\frac{32}{30}$

If you want the answer as a mix fraction like your question began as we can do that by first figuring out how many 30's are in 32 and what is the remainder of that division.

There is one 30 and 32 and so 32-30=2 is the remainder.

$1\frac{2}{30}$

Reduce by dividing top and bottom by 2:

$1\frac{1}{15}$

Now for y:

$\frac{3\frac{1}{6}+3\frac{2}{3}}{2}$

Write the mix fractions as improper fractions:

$\frac{\frac{19}{6}+\frac{11}{3}}{2}$

Dividing by 2 is the same as multiplying by 1/2:

$\frac{19}{12}+\frac{11}{6}$

The least common multiple of 12 and 6 is 12 so I'm going to multiply the second fraction by 2/2 so the denominators will be the same:

$\frac{19}{12}+\frac{22}{12}$

Since the denominators are the same we can write as a single fraction:

$\frac{41}{12}$

How many 12's are in 41? 3 and so the remainder is 41-3(12)=41-36=5.

$3\frac{5}{12}$

So the midpoint is:

$(1\frac{1}{15},3\frac{5}{12})$ .

6 0

3 years ago

Read 2 more answers

1/4d=1/5g(g+e)-h solve for d Please show your work.

loris [4]

Answer:

See below

Step-by-step explanation:

To solve for d, multiply both sides of the equal sign by 4.

4(1/4d) = 4 (1/5g(g+e)-h)

4/4d = 4(1/5 $g^{2}$ + 1/5ge - h)

d = 4/5 $g^{2}$ + 4/5ge - 4h

5 0

2 years ago

Is 5/16 smaller than 3/5

zheka24 [161]

Yes 5/6 is smaller than 3/5

4 0

2 years ago

Read 2 more answers

Volume of this prism

Lyrx [107]

The volume is (area of cross-section) x (length) .

-- The cross-section is a triangle. The area of a triangle is

Area = (1/2) (base) (height) .

In this one, the base is 9/4 m and the height is 3-1/3 m .

Area = (1/2) (9/4 m) (3-1/3 m)

Area = (1/2) (9/4) (10/3)

Area = 90/24 m² .

-- Volume = (area of cross-section) x (length)

Volume = (90/24 m²) x (7-1/3 m)

Volume = (90/24) x (22/3) m³

Volume = (1,980 / 72) m³

Volume = 27.5 m³

5 0

3 years ago

A florist uses 225 branches of winterberry to make 75 wreaths. Based on the ratio or unit rate, how many branches of winterberry

kondaur [170]

Answer:

the number of branches required to use 25 wreaths is 75 branches

Step-by-step explanation:

Given that

The florist used 225 branches of winterberry for making 75 wreaths

First we have to compute the unit rate or the ratio

= 225 ÷ 75

= 3 : 1

Now the number of branches required to use 25 wreaths is

= 3 × 25

= 75 branches

Hence, the number of branches required to use 25 wreaths is 75 branches

6 0

2 years ago

Math question area of figure​

Math question area of figure